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CGP EDU Academic Team
Published on: September 12, 2026
A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 Newtons is applied on the block as shown in the figure, the frictional force between the block and the floor will be
Text Solution
Verified by ExpertsThe correct answer is:
A
Applied force $= 2.5 \, \mathrm{N}$
Limiting friction $= \mu mg = 0.4 \times 2 \times 9.8 = 7.84\,N$
For the given condition applied force is very smaller than limiting friction.
Static friction on a body = Applied force = 2.5 N
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